14[3x-2(x+4)]=28

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Solution for 14[3x-2(x+4)]=28 equation:


Simplifying
14[3x + -2(x + 4)] = 28

Reorder the terms:
14[3x + -2(4 + x)] = 28
14[3x + (4 * -2 + x * -2)] = 28
14[3x + (-8 + -2x)] = 28

Reorder the terms:
14[-8 + 3x + -2x] = 28

Combine like terms: 3x + -2x = 1x
14[-8 + 1x] = 28
[-8 * 14 + 1x * 14] = 28
[-112 + 14x] = 28

Solving
-112 + 14x = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '112' to each side of the equation.
-112 + 112 + 14x = 28 + 112

Combine like terms: -112 + 112 = 0
0 + 14x = 28 + 112
14x = 28 + 112

Combine like terms: 28 + 112 = 140
14x = 140

Divide each side by '14'.
x = 10

Simplifying
x = 10

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